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Solution - Absolute value equations

Exact form: x=3,1
x=3 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+1|=|2x+4|
without the absolute value bars:

|x|=|y||3x+1|=|2x+4|
x=+y(3x+1)=(2x+4)
x=y(3x+1)=(2x+4)
+x=y(3x+1)=(2x+4)
x=y(3x+1)=(2x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+1|=|2x+4|
x=+y , +x=y(3x+1)=(2x+4)
x=y , x=y(3x+1)=(2x+4)

2. Solve the two equations for x

7 additional steps

(3x+1)=(2x+4)

Subtract from both sides:

(3x+1)-2x=(2x+4)-2x

Group like terms:

(3x-2x)+1=(2x+4)-2x

Simplify the arithmetic:

x+1=(2x+4)-2x

Group like terms:

x+1=(2x-2x)+4

Simplify the arithmetic:

x+1=4

Subtract from both sides:

(x+1)-1=4-1

Simplify the arithmetic:

x=41

Simplify the arithmetic:

x=3

11 additional steps

(3x+1)=-(2x+4)

Expand the parentheses:

(3x+1)=-2x-4

Add to both sides:

(3x+1)+2x=(-2x-4)+2x

Group like terms:

(3x+2x)+1=(-2x-4)+2x

Simplify the arithmetic:

5x+1=(-2x-4)+2x

Group like terms:

5x+1=(-2x+2x)-4

Simplify the arithmetic:

5x+1=4

Subtract from both sides:

(5x+1)-1=-4-1

Simplify the arithmetic:

5x=41

Simplify the arithmetic:

5x=5

Divide both sides by :

(5x)5=-55

Simplify the fraction:

x=-55

Simplify the fraction:

x=1

3. List the solutions

x=3,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+1|
y=|2x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.