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Solution - Absolute value equations

Exact form: x=-27,0
x=-\frac{2}{7} , 0
Decimal form: x=0.286,0
x=-0.286 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x+1|+|4x+1|=0

Add |4x+1| to both sides of the equation:

|3x+1|+|4x+1||4x+1|=|4x+1|

Simplify the arithmetic

|3x+1|=|4x+1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+1|=|4x+1|
without the absolute value bars:

|x|=|y||3x+1|=|4x+1|
x=+y(3x+1)=(4x+1)
x=y(3x+1)=(4x+1)
+x=y(3x+1)=(4x+1)
x=y(3x+1)=(4x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+1|=|4x+1|
x=+y , +x=y(3x+1)=(4x+1)
x=y , x=y(3x+1)=(4x+1)

3. Solve the two equations for x

10 additional steps

(3x+1)=-(4x+1)

Expand the parentheses:

(3x+1)=-4x-1

Add to both sides:

(3x+1)+4x=(-4x-1)+4x

Group like terms:

(3x+4x)+1=(-4x-1)+4x

Simplify the arithmetic:

7x+1=(-4x-1)+4x

Group like terms:

7x+1=(-4x+4x)-1

Simplify the arithmetic:

7x+1=1

Subtract from both sides:

(7x+1)-1=-1-1

Simplify the arithmetic:

7x=11

Simplify the arithmetic:

7x=2

Divide both sides by :

(7x)7=-27

Simplify the fraction:

x=-27

11 additional steps

(3x+1)=-(-(4x+1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(3x+1)=4x+1

Subtract from both sides:

(3x+1)-4x=(4x+1)-4x

Group like terms:

(3x-4x)+1=(4x+1)-4x

Simplify the arithmetic:

-x+1=(4x+1)-4x

Group like terms:

-x+1=(4x-4x)+1

Simplify the arithmetic:

x+1=1

Subtract from both sides:

(-x+1)-1=1-1

Simplify the arithmetic:

x=11

Simplify the arithmetic:

x=0

Multiply both sides by :

-x·-1=0·-1

Remove the one(s):

x=0·-1

Multiply by zero:

x=0

4. List the solutions

x=-27,0
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x+1|
y=|4x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.