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Solution - Absolute value equations

Exact form: w=32
w=\frac{3}{2}
Mixed number form: w=112
w=1\frac{1}{2}
Decimal form: w=1.5
w=1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3w5|=|3w4|
without the absolute value bars:

|x|=|y||3w5|=|3w4|
x=+y(3w5)=(3w4)
x=y(3w5)=(3w4)
+x=y(3w5)=(3w4)
x=y(3w5)=(3w4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3w5|=|3w4|
x=+y , +x=y(3w5)=(3w4)
x=y , x=y(3w5)=(3w4)

2. Solve the two equations for w

5 additional steps

(3w-5)=(3w-4)

Subtract from both sides:

(3w-5)-3w=(3w-4)-3w

Group like terms:

(3w-3w)-5=(3w-4)-3w

Simplify the arithmetic:

-5=(3w-4)-3w

Group like terms:

-5=(3w-3w)-4

Simplify the arithmetic:

5=4

The statement is false:

5=4

The equation is false so it has no solution.

12 additional steps

(3w-5)=-(3w-4)

Expand the parentheses:

(3w-5)=-3w+4

Add to both sides:

(3w-5)+3w=(-3w+4)+3w

Group like terms:

(3w+3w)-5=(-3w+4)+3w

Simplify the arithmetic:

6w-5=(-3w+4)+3w

Group like terms:

6w-5=(-3w+3w)+4

Simplify the arithmetic:

6w5=4

Add to both sides:

(6w-5)+5=4+5

Simplify the arithmetic:

6w=4+5

Simplify the arithmetic:

6w=9

Divide both sides by :

(6w)6=96

Simplify the fraction:

w=96

Find the greatest common factor of the numerator and denominator:

w=(3·3)(2·3)

Factor out and cancel the greatest common factor:

w=32

3. Graph

Each line represents the function of one side of the equation:
y=|3w5|
y=|3w4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.