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Solution - Absolute value equations

Exact form:

u = \frac{1}{3}

u=\frac{1}{3}

Decimal form:

u = 0.333

u=0.333

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 3 u - 2 | = | 3 u |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 3 u - 2 \| = \| 3 u \|$
$x = + y$	$(3 u - 2) = (3 u)$
$x = - y$	$(3 u - 2) = - (3 u)$
$+ x = y$	$(3 u - 2) = (3 u)$
$- x = y$	$- (3 u - 2) = (3 u)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 3 u - 2 \| = \| 3 u \|$
$x = + y$ , $+ x = y$	$(3 u - 2) = (3 u)$
$x = - y$ , $- x = y$	$(3 u - 2) = - (3 u)$

2. Solve the two equations for u

4 additional steps

$(3 u - 2) = 3 u$

Subtract from both sides:

$(3 u - 2) - 3 u = (3 u) - 3 u$

Group like terms:

$(3 u - 3 u) - 2 = (3 u) - 3 u$

Simplify the arithmetic:

$- 2 = (3 u) - 3 u$

Simplify the arithmetic:

$- 2 = 0$

The statement is false:

$- 2 = 0$

The equation is false so it has no solution.

9 additional steps

$(3 u - 2) = - 3 u$

Add to both sides:

$(3 u - 2) + 2 = (- 3 u) + 2$

Simplify the arithmetic:

$3 u = (- 3 u) + 2$

Add to both sides:

$(3 u) + 3 u = ((- 3 u) + 2) + 3 u$

Simplify the arithmetic:

$6 u = ((- 3 u) + 2) + 3 u$

Group like terms:

$6 u = (- 3 u + 3 u) + 2$

Simplify the arithmetic:

$6 u = 2$

Divide both sides by :

$\frac{(6 u)}{6} = \frac{2}{6}$

Simplify the fraction:

$u = \frac{2}{6}$

Find the greatest common factor of the numerator and denominator:

$u = \frac{(1 \cdot 2)}{(3 \cdot 2)}$

Factor out and cancel the greatest common factor:

$u = \frac{1}{3}$

3. Graph

Each line represents the function of one side of the equation:
$y = | 3 u - 2 |$
$y = | 3 u |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for u

3. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for u

3. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved