Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: t=6,-25
t=6 , -\frac{2}{5}
Decimal form: t=6,0.4
t=6 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3t2|2|t+2|=0

Add 2|t+2| to both sides of the equation:

|3t2|2|t+2|+2|t+2|=2|t+2|

Simplify the arithmetic

|3t2|=2|t+2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3t2|=2|t+2|
without the absolute value bars:

|x|=|y||3t2|=2|t+2|
x=+y(3t2)=2(t+2)
x=y(3t2)=2((t+2))
+x=y(3t2)=2(t+2)
x=y(3t2)=2(t+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3t2|=2|t+2|
x=+y , +x=y(3t2)=2(t+2)
x=y , x=y(3t2)=2((t+2))

3. Solve the two equations for t

9 additional steps

(3t-2)=2·(t+2)

Expand the parentheses:

(3t-2)=2t+2·2

Simplify the arithmetic:

(3t-2)=2t+4

Subtract from both sides:

(3t-2)-2t=(2t+4)-2t

Group like terms:

(3t-2t)-2=(2t+4)-2t

Simplify the arithmetic:

t-2=(2t+4)-2t

Group like terms:

t-2=(2t-2t)+4

Simplify the arithmetic:

t2=4

Add to both sides:

(t-2)+2=4+2

Simplify the arithmetic:

t=4+2

Simplify the arithmetic:

t=6

14 additional steps

(3t-2)=2·(-(t+2))

Expand the parentheses:

(3t-2)=2·(-t-2)

(3t-2)=2·-t+2·-2

Group like terms:

(3t-2)=(2·-1)t+2·-2

Multiply the coefficients:

(3t-2)=-2t+2·-2

Simplify the arithmetic:

(3t-2)=-2t-4

Add to both sides:

(3t-2)+2t=(-2t-4)+2t

Group like terms:

(3t+2t)-2=(-2t-4)+2t

Simplify the arithmetic:

5t-2=(-2t-4)+2t

Group like terms:

5t-2=(-2t+2t)-4

Simplify the arithmetic:

5t2=4

Add to both sides:

(5t-2)+2=-4+2

Simplify the arithmetic:

5t=4+2

Simplify the arithmetic:

5t=2

Divide both sides by :

(5t)5=-25

Simplify the fraction:

t=-25

4. List the solutions

t=6,-25
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3t2|
y=2|t+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.