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Solution - Absolute value equations

Exact form: t=23,-2
t=\frac{2}{3} , -2
Decimal form: t=0.667,2
t=0.667 , -2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3t2|=|3t+2|
without the absolute value bars:

|x|=|y||3t2|=|3t+2|
x=+y(3t2)=(3t+2)
x=y(3t2)=(3t+2)
+x=y(3t2)=(3t+2)
x=y(3t2)=(3t+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3t2|=|3t+2|
x=+y , +x=y(3t2)=(3t+2)
x=y , x=y(3t2)=(3t+2)

2. Solve the two equations for t

11 additional steps

(3t-2)=(-3t+2)

Add to both sides:

(3t-2)+3t=(-3t+2)+3t

Group like terms:

(3t+3t)-2=(-3t+2)+3t

Simplify the arithmetic:

6t-2=(-3t+2)+3t

Group like terms:

6t-2=(-3t+3t)+2

Simplify the arithmetic:

6t2=2

Add to both sides:

(6t-2)+2=2+2

Simplify the arithmetic:

6t=2+2

Simplify the arithmetic:

6t=4

Divide both sides by :

(6t)6=46

Simplify the fraction:

t=46

Find the greatest common factor of the numerator and denominator:

t=(2·2)(3·2)

Factor out and cancel the greatest common factor:

t=23

5 additional steps

(3t-2)=-(-3t+2)

Expand the parentheses:

(3t-2)=3t-2

Subtract from both sides:

(3t-2)-3t=(3t-2)-3t

Group like terms:

(3t-3t)-2=(3t-2)-3t

Simplify the arithmetic:

-2=(3t-2)-3t

Group like terms:

-2=(3t-3t)-2

Simplify the arithmetic:

2=2

3. List the solutions

t=23,-2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3t2|
y=|3t+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.