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Solution - Absolute value equations

Exact form: s=10,12
s=10 , \frac{1}{2}
Decimal form: s=10,0.5
s=10 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3s11|=|s+9|
without the absolute value bars:

|x|=|y||3s11|=|s+9|
x=+y(3s11)=(s+9)
x=y(3s11)=(s+9)
+x=y(3s11)=(s+9)
x=y(3s11)=(s+9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3s11|=|s+9|
x=+y , +x=y(3s11)=(s+9)
x=y , x=y(3s11)=(s+9)

2. Solve the two equations for s

11 additional steps

(3s-11)=(s+9)

Subtract from both sides:

(3s-11)-s=(s+9)-s

Group like terms:

(3s-s)-11=(s+9)-s

Simplify the arithmetic:

2s-11=(s+9)-s

Group like terms:

2s-11=(s-s)+9

Simplify the arithmetic:

2s-11=9

Add to both sides:

(2s-11)+11=9+11

Simplify the arithmetic:

2s=9+11

Simplify the arithmetic:

2s=20

Divide both sides by :

(2s)2=202

Simplify the fraction:

s=202

Find the greatest common factor of the numerator and denominator:

s=(10·2)(1·2)

Factor out and cancel the greatest common factor:

s=10

12 additional steps

(3s-11)=-(s+9)

Expand the parentheses:

(3s-11)=-s-9

Add to both sides:

(3s-11)+s=(-s-9)+s

Group like terms:

(3s+s)-11=(-s-9)+s

Simplify the arithmetic:

4s-11=(-s-9)+s

Group like terms:

4s-11=(-s+s)-9

Simplify the arithmetic:

4s-11=-9

Add to both sides:

(4s-11)+11=-9+11

Simplify the arithmetic:

4s=-9+11

Simplify the arithmetic:

4s=2

Divide both sides by :

(4s)4=24

Simplify the fraction:

s=24

Find the greatest common factor of the numerator and denominator:

s=(1·2)(2·2)

Factor out and cancel the greatest common factor:

s=12

3. List the solutions

s=10,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3s11|
y=|s+9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.