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Solution - Absolute value equations

Exact form: s=2,1
s=-2 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3s+3|=|s5|
without the absolute value bars:

|x|=|y||3s+3|=|s5|
x=+y(3s+3)=(s5)
x=y(3s+3)=(s5)
+x=y(3s+3)=(s5)
x=y(3s+3)=(s5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3s+3|=|s5|
x=+y , +x=y(3s+3)=(s5)
x=y , x=y(3s+3)=(s5)

2. Solve the two equations for s

11 additional steps

(3s+3)=(-s-5)

Add to both sides:

(3s+3)+s=(-s-5)+s

Group like terms:

(3s+s)+3=(-s-5)+s

Simplify the arithmetic:

4s+3=(-s-5)+s

Group like terms:

4s+3=(-s+s)-5

Simplify the arithmetic:

4s+3=-5

Subtract from both sides:

(4s+3)-3=-5-3

Simplify the arithmetic:

4s=-5-3

Simplify the arithmetic:

4s=-8

Divide both sides by :

(4s)4=-84

Simplify the fraction:

s=-84

Find the greatest common factor of the numerator and denominator:

s=(-2·4)(1·4)

Factor out and cancel the greatest common factor:

s=-2

11 additional steps

(3s+3)=-(-s-5)

Expand the parentheses:

(3s+3)=s+5

Subtract from both sides:

(3s+3)-s=(s+5)-s

Group like terms:

(3s-s)+3=(s+5)-s

Simplify the arithmetic:

2s+3=(s+5)-s

Group like terms:

2s+3=(s-s)+5

Simplify the arithmetic:

2s+3=5

Subtract from both sides:

(2s+3)-3=5-3

Simplify the arithmetic:

2s=5-3

Simplify the arithmetic:

2s=2

Divide both sides by :

(2s)2=22

Simplify the fraction:

s=22

Simplify the fraction:

s=1

3. List the solutions

s=2,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3s+3|
y=|s5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.