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Solution - Absolute value equations

Exact form: n=2
n=2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3n9|=|3n3|
without the absolute value bars:

|x|=|y||3n9|=|3n3|
x=+y(3n9)=(3n3)
x=y(3n9)=(3n3)
+x=y(3n9)=(3n3)
x=y(3n9)=(3n3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3n9|=|3n3|
x=+y , +x=y(3n9)=(3n3)
x=y , x=y(3n9)=(3n3)

2. Solve the two equations for n

5 additional steps

(3n-9)=(3n-3)

Subtract from both sides:

(3n-9)-3n=(3n-3)-3n

Group like terms:

(3n-3n)-9=(3n-3)-3n

Simplify the arithmetic:

-9=(3n-3)-3n

Group like terms:

-9=(3n-3n)-3

Simplify the arithmetic:

9=3

The statement is false:

9=3

The equation is false so it has no solution.

12 additional steps

(3n-9)=-(3n-3)

Expand the parentheses:

(3n-9)=-3n+3

Add to both sides:

(3n-9)+3n=(-3n+3)+3n

Group like terms:

(3n+3n)-9=(-3n+3)+3n

Simplify the arithmetic:

6n-9=(-3n+3)+3n

Group like terms:

6n-9=(-3n+3n)+3

Simplify the arithmetic:

6n9=3

Add to both sides:

(6n-9)+9=3+9

Simplify the arithmetic:

6n=3+9

Simplify the arithmetic:

6n=12

Divide both sides by :

(6n)6=126

Simplify the fraction:

n=126

Find the greatest common factor of the numerator and denominator:

n=(2·6)(1·6)

Factor out and cancel the greatest common factor:

n=2

3. Graph

Each line represents the function of one side of the equation:
y=|3n9|
y=|3n3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.