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Solution - Absolute value equations

Exact form: m=6,-25
m=6 , -\frac{2}{5}
Decimal form: m=6,0.4
m=6 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3m2|=2|m+2|
without the absolute value bars:

|x|=|y||3m2|=2|m+2|
x=+y(3m2)=2(m+2)
x=y(3m2)=2((m+2))
+x=y(3m2)=2(m+2)
x=y(3m2)=2(m+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3m2|=2|m+2|
x=+y , +x=y(3m2)=2(m+2)
x=y , x=y(3m2)=2((m+2))

2. Solve the two equations for m

9 additional steps

(3m-2)=2·(m+2)

Expand the parentheses:

(3m-2)=2m+2·2

Simplify the arithmetic:

(3m-2)=2m+4

Subtract from both sides:

(3m-2)-2m=(2m+4)-2m

Group like terms:

(3m-2m)-2=(2m+4)-2m

Simplify the arithmetic:

m-2=(2m+4)-2m

Group like terms:

m-2=(2m-2m)+4

Simplify the arithmetic:

m-2=4

Add to both sides:

(m-2)+2=4+2

Simplify the arithmetic:

m=4+2

Simplify the arithmetic:

m=6

14 additional steps

(3m-2)=2·(-(m+2))

Expand the parentheses:

(3m-2)=2·(-m-2)

(3m-2)=2·-m+2·-2

Group like terms:

(3m-2)=(2·-1)m+2·-2

Multiply the coefficients:

(3m-2)=-2m+2·-2

Simplify the arithmetic:

(3m-2)=-2m-4

Add to both sides:

(3m-2)+2m=(-2m-4)+2m

Group like terms:

(3m+2m)-2=(-2m-4)+2m

Simplify the arithmetic:

5m-2=(-2m-4)+2m

Group like terms:

5m-2=(-2m+2m)-4

Simplify the arithmetic:

5m-2=-4

Add to both sides:

(5m-2)+2=-4+2

Simplify the arithmetic:

5m=-4+2

Simplify the arithmetic:

5m=-2

Divide both sides by :

(5m)5=-25

Simplify the fraction:

m=-25

3. List the solutions

m=6,-25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3m2|
y=2|m+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.