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Solution - Absolute value equations

Exact form: m=-7,35
m=-7 , \frac{3}{5}
Decimal form: m=7,0.6
m=-7 , 0.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3m+2|+|2m+5|=0

Add |2m+5| to both sides of the equation:

|3m+2|+|2m+5||2m+5|=|2m+5|

Simplify the arithmetic

|3m+2|=|2m+5|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3m+2|=|2m+5|
without the absolute value bars:

|x|=|y||3m+2|=|2m+5|
x=+y(3m+2)=(2m+5)
x=y(3m+2)=(2m+5)
+x=y(3m+2)=(2m+5)
x=y(3m+2)=(2m+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3m+2|=|2m+5|
x=+y , +x=y(3m+2)=(2m+5)
x=y , x=y(3m+2)=(2m+5)

3. Solve the two equations for m

8 additional steps

(3m+2)=-(-2m+5)

Expand the parentheses:

(3m+2)=2m-5

Subtract from both sides:

(3m+2)-2m=(2m-5)-2m

Group like terms:

(3m-2m)+2=(2m-5)-2m

Simplify the arithmetic:

m+2=(2m-5)-2m

Group like terms:

m+2=(2m-2m)-5

Simplify the arithmetic:

m+2=-5

Subtract from both sides:

(m+2)-2=-5-2

Simplify the arithmetic:

m=-5-2

Simplify the arithmetic:

m=-7

10 additional steps

(3m+2)=-(-(-2m+5))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(3m+2)=-2m+5

Add to both sides:

(3m+2)+2m=(-2m+5)+2m

Group like terms:

(3m+2m)+2=(-2m+5)+2m

Simplify the arithmetic:

5m+2=(-2m+5)+2m

Group like terms:

5m+2=(-2m+2m)+5

Simplify the arithmetic:

5m+2=5

Subtract from both sides:

(5m+2)-2=5-2

Simplify the arithmetic:

5m=5-2

Simplify the arithmetic:

5m=3

Divide both sides by :

(5m)5=35

Simplify the fraction:

m=35

4. List the solutions

m=-7,35
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3m+2|
y=|2m+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.