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Solution - Absolute value equations

Exact form: k=2,0
k=2 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3k2|=|k+2|
without the absolute value bars:

|x|=|y||3k2|=|k+2|
x=+y(3k2)=(k+2)
x=y(3k2)=(k+2)
+x=y(3k2)=(k+2)
x=y(3k2)=(k+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3k2|=|k+2|
x=+y , +x=y(3k2)=(k+2)
x=y , x=y(3k2)=(k+2)

2. Solve the two equations for k

11 additional steps

(3k-2)=(k+2)

Subtract from both sides:

(3k-2)-k=(k+2)-k

Group like terms:

(3k-k)-2=(k+2)-k

Simplify the arithmetic:

2k-2=(k+2)-k

Group like terms:

2k-2=(k-k)+2

Simplify the arithmetic:

2k2=2

Add to both sides:

(2k-2)+2=2+2

Simplify the arithmetic:

2k=2+2

Simplify the arithmetic:

2k=4

Divide both sides by :

(2k)2=42

Simplify the fraction:

k=42

Find the greatest common factor of the numerator and denominator:

k=(2·2)(1·2)

Factor out and cancel the greatest common factor:

k=2

9 additional steps

(3k-2)=-(k+2)

Expand the parentheses:

(3k-2)=-k-2

Add to both sides:

(3k-2)+k=(-k-2)+k

Group like terms:

(3k+k)-2=(-k-2)+k

Simplify the arithmetic:

4k-2=(-k-2)+k

Group like terms:

4k-2=(-k+k)-2

Simplify the arithmetic:

4k2=2

Add to both sides:

(4k-2)+2=-2+2

Simplify the arithmetic:

4k=2+2

Simplify the arithmetic:

4k=0

Divide both sides by the coefficient:

k=0

3. List the solutions

k=2,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3k2|
y=|k+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.