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Solution - Absolute value equations

Exact form: h=-170,176
h=-\frac{1}{70} , \frac{1}{76}
Decimal form: h=0.014,0.013
h=-0.014 , 0.013

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3h1|=|73h|
without the absolute value bars:

|x|=|y||3h1|=|73h|
x=+y(3h1)=(73h)
x=y(3h1)=(73h)
+x=y(3h1)=(73h)
x=y(3h1)=(73h)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3h1|=|73h|
x=+y , +x=y(3h1)=(73h)
x=y , x=y(3h1)=(73h)

2. Solve the two equations for h

10 additional steps

(3h-1)=73h

Subtract from both sides:

(3h-1)-73h=(73h)-73h

Group like terms:

(3h-73h)-1=(73h)-73h

Simplify the arithmetic:

-70h-1=(73h)-73h

Simplify the arithmetic:

-70h-1=0

Add to both sides:

(-70h-1)+1=0+1

Simplify the arithmetic:

-70h=0+1

Simplify the arithmetic:

-70h=1

Divide both sides by :

(-70h)-70=1-70

Cancel out the negatives:

70h70=1-70

Simplify the fraction:

h=1-70

Move the negative sign from the denominator to the numerator:

h=-170

7 additional steps

(3h-1)=-73h

Add to both sides:

(3h-1)+1=(-73h)+1

Simplify the arithmetic:

3h=(-73h)+1

Add to both sides:

(3h)+73h=((-73h)+1)+73h

Simplify the arithmetic:

76h=((-73h)+1)+73h

Group like terms:

76h=(-73h+73h)+1

Simplify the arithmetic:

76h=1

Divide both sides by :

(76h)76=176

Simplify the fraction:

h=176

3. List the solutions

h=-170,176
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3h1|
y=|73h|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.