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Solution - Absolute value equations

Exact form: h=-43
h=-\frac{4}{3}
Mixed number form: h=-113
h=-1\frac{1}{3}
Decimal form: h=1.333
h=-1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3h+1|=|3h+7|
without the absolute value bars:

|x|=|y||3h+1|=|3h+7|
x=+y(3h+1)=(3h+7)
x=y(3h+1)=(3h+7)
+x=y(3h+1)=(3h+7)
x=y(3h+1)=(3h+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3h+1|=|3h+7|
x=+y , +x=y(3h+1)=(3h+7)
x=y , x=y(3h+1)=(3h+7)

2. Solve the two equations for h

5 additional steps

(3h+1)=(3h+7)

Subtract from both sides:

(3h+1)-3h=(3h+7)-3h

Group like terms:

(3h-3h)+1=(3h+7)-3h

Simplify the arithmetic:

1=(3h+7)-3h

Group like terms:

1=(3h-3h)+7

Simplify the arithmetic:

1=7

The statement is false:

1=7

The equation is false so it has no solution.

12 additional steps

(3h+1)=-(3h+7)

Expand the parentheses:

(3h+1)=-3h-7

Add to both sides:

(3h+1)+3h=(-3h-7)+3h

Group like terms:

(3h+3h)+1=(-3h-7)+3h

Simplify the arithmetic:

6h+1=(-3h-7)+3h

Group like terms:

6h+1=(-3h+3h)-7

Simplify the arithmetic:

6h+1=-7

Subtract from both sides:

(6h+1)-1=-7-1

Simplify the arithmetic:

6h=-7-1

Simplify the arithmetic:

6h=-8

Divide both sides by :

(6h)6=-86

Simplify the fraction:

h=-86

Find the greatest common factor of the numerator and denominator:

h=(-4·2)(3·2)

Factor out and cancel the greatest common factor:

h=-43

3. Graph

Each line represents the function of one side of the equation:
y=|3h+1|
y=|3h+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.