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Solution - Absolute value equations

Exact form: c=-1,-52
c=-1 , -\frac{5}{2}
Mixed number form: c=-1,-212
c=-1 , -2\frac{1}{2}
Decimal form: c=1,2.5
c=-1 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3c+6|=|c+4|
without the absolute value bars:

|x|=|y||3c+6|=|c+4|
x=+y(3c+6)=(c+4)
x=y(3c+6)=(c+4)
+x=y(3c+6)=(c+4)
x=y(3c+6)=(c+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3c+6|=|c+4|
x=+y , +x=y(3c+6)=(c+4)
x=y , x=y(3c+6)=(c+4)

2. Solve the two equations for c

10 additional steps

(3c+6)=(c+4)

Subtract from both sides:

(3c+6)-c=(c+4)-c

Group like terms:

(3c-c)+6=(c+4)-c

Simplify the arithmetic:

2c+6=(c+4)-c

Group like terms:

2c+6=(c-c)+4

Simplify the arithmetic:

2c+6=4

Subtract from both sides:

(2c+6)-6=4-6

Simplify the arithmetic:

2c=46

Simplify the arithmetic:

2c=2

Divide both sides by :

(2c)2=-22

Simplify the fraction:

c=-22

Simplify the fraction:

c=1

12 additional steps

(3c+6)=-(c+4)

Expand the parentheses:

(3c+6)=-c-4

Add to both sides:

(3c+6)+c=(-c-4)+c

Group like terms:

(3c+c)+6=(-c-4)+c

Simplify the arithmetic:

4c+6=(-c-4)+c

Group like terms:

4c+6=(-c+c)-4

Simplify the arithmetic:

4c+6=4

Subtract from both sides:

(4c+6)-6=-4-6

Simplify the arithmetic:

4c=46

Simplify the arithmetic:

4c=10

Divide both sides by :

(4c)4=-104

Simplify the fraction:

c=-104

Find the greatest common factor of the numerator and denominator:

c=(-5·2)(2·2)

Factor out and cancel the greatest common factor:

c=-52

3. List the solutions

c=-1,-52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3c+6|
y=|c+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.