Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: c=7,3
c=7 , -3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3c+4|=|2c+11|
without the absolute value bars:

|x|=|y||3c+4|=|2c+11|
x=+y(3c+4)=(2c+11)
x=y(3c+4)=(2c+11)
+x=y(3c+4)=(2c+11)
x=y(3c+4)=(2c+11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3c+4|=|2c+11|
x=+y , +x=y(3c+4)=(2c+11)
x=y , x=y(3c+4)=(2c+11)

2. Solve the two equations for c

7 additional steps

(3c+4)=(2c+11)

Subtract from both sides:

(3c+4)-2c=(2c+11)-2c

Group like terms:

(3c-2c)+4=(2c+11)-2c

Simplify the arithmetic:

c+4=(2c+11)-2c

Group like terms:

c+4=(2c-2c)+11

Simplify the arithmetic:

c+4=11

Subtract from both sides:

(c+4)-4=11-4

Simplify the arithmetic:

c=114

Simplify the arithmetic:

c=7

12 additional steps

(3c+4)=-(2c+11)

Expand the parentheses:

(3c+4)=-2c-11

Add to both sides:

(3c+4)+2c=(-2c-11)+2c

Group like terms:

(3c+2c)+4=(-2c-11)+2c

Simplify the arithmetic:

5c+4=(-2c-11)+2c

Group like terms:

5c+4=(-2c+2c)-11

Simplify the arithmetic:

5c+4=11

Subtract from both sides:

(5c+4)-4=-11-4

Simplify the arithmetic:

5c=114

Simplify the arithmetic:

5c=15

Divide both sides by :

(5c)5=-155

Simplify the fraction:

c=-155

Find the greatest common factor of the numerator and denominator:

c=(-3·5)(1·5)

Factor out and cancel the greatest common factor:

c=3

3. List the solutions

c=7,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3c+4|
y=|2c+11|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.