Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: b=5,-12
b=5 , -\frac{1}{2}
Decimal form: b=5,0.5
b=5 , -0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3b4|=|b+6|
without the absolute value bars:

|x|=|y||3b4|=|b+6|
x=+y(3b4)=(b+6)
x=y(3b4)=(b+6)
+x=y(3b4)=(b+6)
x=y(3b4)=(b+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3b4|=|b+6|
x=+y , +x=y(3b4)=(b+6)
x=y , x=y(3b4)=(b+6)

2. Solve the two equations for b

11 additional steps

(3b-4)=(b+6)

Subtract from both sides:

(3b-4)-b=(b+6)-b

Group like terms:

(3b-b)-4=(b+6)-b

Simplify the arithmetic:

2b-4=(b+6)-b

Group like terms:

2b-4=(b-b)+6

Simplify the arithmetic:

2b-4=6

Add to both sides:

(2b-4)+4=6+4

Simplify the arithmetic:

2b=6+4

Simplify the arithmetic:

2b=10

Divide both sides by :

(2b)2=102

Simplify the fraction:

b=102

Find the greatest common factor of the numerator and denominator:

b=(5·2)(1·2)

Factor out and cancel the greatest common factor:

b=5

12 additional steps

(3b-4)=-(b+6)

Expand the parentheses:

(3b-4)=-b-6

Add to both sides:

(3b-4)+b=(-b-6)+b

Group like terms:

(3b+b)-4=(-b-6)+b

Simplify the arithmetic:

4b-4=(-b-6)+b

Group like terms:

4b-4=(-b+b)-6

Simplify the arithmetic:

4b-4=-6

Add to both sides:

(4b-4)+4=-6+4

Simplify the arithmetic:

4b=-6+4

Simplify the arithmetic:

4b=-2

Divide both sides by :

(4b)4=-24

Simplify the fraction:

b=-24

Find the greatest common factor of the numerator and denominator:

b=(-1·2)(2·2)

Factor out and cancel the greatest common factor:

b=-12

3. List the solutions

b=5,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3b4|
y=|b+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.