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Solution - Absolute value equations

Exact form: a=-1,12
a=-1 , \frac{1}{2}
Decimal form: a=1,0.5
a=-1 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3a6|=|9a|
without the absolute value bars:

|x|=|y||3a6|=|9a|
x=+y(3a6)=(9a)
x=y(3a6)=(9a)
+x=y(3a6)=(9a)
x=y(3a6)=(9a)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3a6|=|9a|
x=+y , +x=y(3a6)=(9a)
x=y , x=y(3a6)=(9a)

2. Solve the two equations for a

11 additional steps

(3a-6)=9a

Subtract from both sides:

(3a-6)-9a=(9a)-9a

Group like terms:

(3a-9a)-6=(9a)-9a

Simplify the arithmetic:

-6a-6=(9a)-9a

Simplify the arithmetic:

6a6=0

Add to both sides:

(-6a-6)+6=0+6

Simplify the arithmetic:

6a=0+6

Simplify the arithmetic:

6a=6

Divide both sides by :

(-6a)-6=6-6

Cancel out the negatives:

6a6=6-6

Simplify the fraction:

a=6-6

Move the negative sign from the denominator to the numerator:

a=-66

Simplify the fraction:

a=1

9 additional steps

(3a-6)=-9a

Add to both sides:

(3a-6)+6=(-9a)+6

Simplify the arithmetic:

3a=(-9a)+6

Add to both sides:

(3a)+9a=((-9a)+6)+9a

Simplify the arithmetic:

12a=((-9a)+6)+9a

Group like terms:

12a=(-9a+9a)+6

Simplify the arithmetic:

12a=6

Divide both sides by :

(12a)12=612

Simplify the fraction:

a=612

Find the greatest common factor of the numerator and denominator:

a=(1·6)(2·6)

Factor out and cancel the greatest common factor:

a=12

3. List the solutions

a=-1,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3a6|
y=|9a|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.