Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: a=152,-54
a=\frac{15}{2} , -\frac{5}{4}
Mixed number form: a=712,-114
a=7\frac{1}{2} , -1\frac{1}{4}
Decimal form: a=7.5,1.25
a=7.5 , -1.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3a5|=|a+10|
without the absolute value bars:

|x|=|y||3a5|=|a+10|
x=+y(3a5)=(a+10)
x=y(3a5)=(a+10)
+x=y(3a5)=(a+10)
x=y(3a5)=(a+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3a5|=|a+10|
x=+y , +x=y(3a5)=(a+10)
x=y , x=y(3a5)=(a+10)

2. Solve the two equations for a

9 additional steps

(3a-5)=(a+10)

Subtract from both sides:

(3a-5)-a=(a+10)-a

Group like terms:

(3a-a)-5=(a+10)-a

Simplify the arithmetic:

2a-5=(a+10)-a

Group like terms:

2a-5=(a-a)+10

Simplify the arithmetic:

2a5=10

Add to both sides:

(2a-5)+5=10+5

Simplify the arithmetic:

2a=10+5

Simplify the arithmetic:

2a=15

Divide both sides by :

(2a)2=152

Simplify the fraction:

a=152

10 additional steps

(3a-5)=-(a+10)

Expand the parentheses:

(3a-5)=-a-10

Add to both sides:

(3a-5)+a=(-a-10)+a

Group like terms:

(3a+a)-5=(-a-10)+a

Simplify the arithmetic:

4a-5=(-a-10)+a

Group like terms:

4a-5=(-a+a)-10

Simplify the arithmetic:

4a5=10

Add to both sides:

(4a-5)+5=-10+5

Simplify the arithmetic:

4a=10+5

Simplify the arithmetic:

4a=5

Divide both sides by :

(4a)4=-54

Simplify the fraction:

a=-54

3. List the solutions

a=152,-54
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3a5|
y=|a+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.