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Solution - Absolute value equations

Exact form: a=1,3
a=1 , 3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3a4|+|2a1|=0

Add |2a1| to both sides of the equation:

|3a4|+|2a1||2a1|=|2a1|

Simplify the arithmetic

|3a4|=|2a1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3a4|=|2a1|
without the absolute value bars:

|x|=|y||3a4|=|2a1|
x=+y(3a4)=(2a1)
x=y(3a4)=(2a1)
+x=y(3a4)=(2a1)
x=y(3a4)=(2a1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3a4|=|2a1|
x=+y , +x=y(3a4)=(2a1)
x=y , x=y(3a4)=(2a1)

3. Solve the two equations for a

11 additional steps

(3a-4)=-(2a-1)

Expand the parentheses:

(3a-4)=-2a+1

Add to both sides:

(3a-4)+2a=(-2a+1)+2a

Group like terms:

(3a+2a)-4=(-2a+1)+2a

Simplify the arithmetic:

5a-4=(-2a+1)+2a

Group like terms:

5a-4=(-2a+2a)+1

Simplify the arithmetic:

5a4=1

Add to both sides:

(5a-4)+4=1+4

Simplify the arithmetic:

5a=1+4

Simplify the arithmetic:

5a=5

Divide both sides by :

(5a)5=55

Simplify the fraction:

a=55

Simplify the fraction:

a=1

8 additional steps

(3a-4)=-(-(2a-1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(3a-4)=2a-1

Subtract from both sides:

(3a-4)-2a=(2a-1)-2a

Group like terms:

(3a-2a)-4=(2a-1)-2a

Simplify the arithmetic:

a-4=(2a-1)-2a

Group like terms:

a-4=(2a-2a)-1

Simplify the arithmetic:

a4=1

Add to both sides:

(a-4)+4=-1+4

Simplify the arithmetic:

a=1+4

Simplify the arithmetic:

a=3

4. List the solutions

a=1,3
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3a4|
y=|2a1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.