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Solution - Absolute value equations

Exact form: a=-23
a=-\frac{2}{3}
Decimal form: a=0.667
a=-0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3a+8|=|3a4|
without the absolute value bars:

|x|=|y||3a+8|=|3a4|
x=+y(3a+8)=(3a4)
x=y(3a+8)=(3a4)
+x=y(3a+8)=(3a4)
x=y(3a+8)=(3a4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3a+8|=|3a4|
x=+y , +x=y(3a+8)=(3a4)
x=y , x=y(3a+8)=(3a4)

2. Solve the two equations for a

5 additional steps

(3a+8)=(3a-4)

Subtract from both sides:

(3a+8)-3a=(3a-4)-3a

Group like terms:

(3a-3a)+8=(3a-4)-3a

Simplify the arithmetic:

8=(3a-4)-3a

Group like terms:

8=(3a-3a)-4

Simplify the arithmetic:

8=4

The statement is false:

8=4

The equation is false so it has no solution.

12 additional steps

(3a+8)=-(3a-4)

Expand the parentheses:

(3a+8)=-3a+4

Add to both sides:

(3a+8)+3a=(-3a+4)+3a

Group like terms:

(3a+3a)+8=(-3a+4)+3a

Simplify the arithmetic:

6a+8=(-3a+4)+3a

Group like terms:

6a+8=(-3a+3a)+4

Simplify the arithmetic:

6a+8=4

Subtract from both sides:

(6a+8)-8=4-8

Simplify the arithmetic:

6a=48

Simplify the arithmetic:

6a=4

Divide both sides by :

(6a)6=-46

Simplify the fraction:

a=-46

Find the greatest common factor of the numerator and denominator:

a=(-2·2)(3·2)

Factor out and cancel the greatest common factor:

a=-23

3. Graph

Each line represents the function of one side of the equation:
y=|3a+8|
y=|3a4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.