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Solution - Absolute value equations

Exact form:

x = - \frac{7}{26}, \frac{7}{38}

x=-\frac{7}{26} , \frac{7}{38}

Decimal form:

x = - 0.269, 0.184

x=-0.269 , 0.184

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 32 x | = | 6 x - 7 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 32 x \| = \| 6 x - 7 \|$
$x = + y$	$(32 x) = (6 x - 7)$
$x = - y$	$(32 x) = - (6 x - 7)$
$+ x = y$	$(32 x) = (6 x - 7)$
$- x = y$	$- (32 x) = (6 x - 7)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 32 x \| = \| 6 x - 7 \|$
$x = + y$ , $+ x = y$	$(32 x) = (6 x - 7)$
$x = - y$ , $- x = y$	$(32 x) = - (6 x - 7)$

2. Solve the two equations for x

5 additional steps

$32 x = (6 x - 7)$

Subtract from both sides:

$(32 x) - 6 x = (6 x - 7) - 6 x$

Simplify the arithmetic:

$26 x = (6 x - 7) - 6 x$

Group like terms:

$26 x = (6 x - 6 x) - 7$

Simplify the arithmetic:

$26 x = - 7$

Divide both sides by :

$\frac{(26 x)}{26} = \frac{- 7}{26}$

Simplify the fraction:

$x = \frac{- 7}{26}$

6 additional steps

$32 x = - (6 x - 7)$

Expand the parentheses:

$32 x = - 6 x + 7$

Add to both sides:

$(32 x) + 6 x = (- 6 x + 7) + 6 x$

Simplify the arithmetic:

$38 x = (- 6 x + 7) + 6 x$

Group like terms:

$38 x = (- 6 x + 6 x) + 7$

Simplify the arithmetic:

$38 x = 7$

Divide both sides by :

$\frac{(38 x)}{38} = \frac{7}{38}$

Simplify the fraction:

$x = \frac{7}{38}$

3. List the solutions

$x = - \frac{7}{26}, \frac{7}{38}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 32 x |$
$y = | 6 x - 7 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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