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Solution - Absolute value equations

Exact form: x=1,1.645
x=-1 , 1.645

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+3.1|=|2.1x+2|
without the absolute value bars:

|x|=|y||x+3.1|=|2.1x+2|
x=+y(x+3.1)=(2.1x+2)
x=y(x+3.1)=(2.1x+2)
+x=y(x+3.1)=(2.1x+2)
x=y(x+3.1)=(2.1x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+3.1|=|2.1x+2|
x=+y , +x=y(x+3.1)=(2.1x+2)
x=y , x=y(x+3.1)=(2.1x+2)

2. Solve the two equations for x

10 additional steps

(-x+3.1)=(-2.1x+2)

Add to both sides:

(-x+3.1)+2.1x=(-2.1x+2)+2.1x

Group like terms:

(-x+2.1x)+3.1=(-2.1x+2)+2.1x

Simplify the arithmetic:

1.1x+3.1=(-2.1x+2)+2.1x

Group like terms:

1.1x+3.1=(-2.1x+2.1x)+2

Simplify the arithmetic:

1.1x+3.1=2

Subtract from both sides:

(1.1x+3.1)-3.1=2-3.1

Simplify the arithmetic:

1.1x=23.1

Simplify the arithmetic:

1.1x=1.1

Divide both sides by :

(1.1x)1.1=-1.11.1

Simplify the arithmetic:

x=-1.11.1

Simplify the arithmetic:

x=1

13 additional steps

(-x+3.1)=-(-2.1x+2)

Expand the parentheses:

(-x+3.1)=2.1x-2

Subtract from both sides:

(-x+3.1)-2.1x=(2.1x-2)-2.1x

Group like terms:

(-x-2.1x)+3.1=(2.1x-2)-2.1x

Simplify the arithmetic:

-3.1x+3.1=(2.1x-2)-2.1x

Group like terms:

-3.1x+3.1=(2.1x-2.1x)-2

Simplify the arithmetic:

3.1x+3.1=2

Subtract from both sides:

(-3.1x+3.1)-3.1=-2-3.1

Simplify the arithmetic:

3.1x=23.1

Simplify the arithmetic:

3.1x=5.1

Divide both sides by :

(-3.1x)-3.1=-5.1-3.1

Cancel out the negatives:

3.1x3.1=-5.1-3.1

Simplify the arithmetic:

x=-5.1-3.1

Cancel out the negatives:

x=5.13.1

Simplify the arithmetic:

x=1.6452

3. List the solutions

x=1,1.645
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+3.1|
y=|2.1x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.