Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=15,-53
x=\frac{1}{5} , -\frac{5}{3}
Mixed number form: x=15,-123
x=\frac{1}{5} , -1\frac{2}{3}
Decimal form: x=0.2,1.667
x=0.2 , -1.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+3|=|4x+2|
without the absolute value bars:

|x|=|y||x+3|=|4x+2|
x=+y(x+3)=(4x+2)
x=y(x+3)=(4x+2)
+x=y(x+3)=(4x+2)
x=y(x+3)=(4x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+3|=|4x+2|
x=+y , +x=y(x+3)=(4x+2)
x=y , x=y(x+3)=(4x+2)

2. Solve the two equations for x

11 additional steps

(-x+3)=(4x+2)

Subtract from both sides:

(-x+3)-4x=(4x+2)-4x

Group like terms:

(-x-4x)+3=(4x+2)-4x

Simplify the arithmetic:

-5x+3=(4x+2)-4x

Group like terms:

-5x+3=(4x-4x)+2

Simplify the arithmetic:

5x+3=2

Subtract from both sides:

(-5x+3)-3=2-3

Simplify the arithmetic:

5x=23

Simplify the arithmetic:

5x=1

Divide both sides by :

(-5x)-5=-1-5

Cancel out the negatives:

5x5=-1-5

Simplify the fraction:

x=-1-5

Cancel out the negatives:

x=15

10 additional steps

(-x+3)=-(4x+2)

Expand the parentheses:

(-x+3)=-4x-2

Add to both sides:

(-x+3)+4x=(-4x-2)+4x

Group like terms:

(-x+4x)+3=(-4x-2)+4x

Simplify the arithmetic:

3x+3=(-4x-2)+4x

Group like terms:

3x+3=(-4x+4x)-2

Simplify the arithmetic:

3x+3=2

Subtract from both sides:

(3x+3)-3=-2-3

Simplify the arithmetic:

3x=23

Simplify the arithmetic:

3x=5

Divide both sides by :

(3x)3=-53

Simplify the fraction:

x=-53

3. List the solutions

x=15,-53
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+3|
y=|4x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.