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Solution - Absolute value equations

Exact form: i=-320,328
i=-\frac{3}{20} , \frac{3}{28}
Decimal form: i=0.15,0.107
i=-0.15 , 0.107

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|4i+3|+|24i|=0

Add |24i| to both sides of the equation:

|4i+3|+|24i||24i|=|24i|

Simplify the arithmetic

|4i+3|=|24i|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4i+3|=|24i|
without the absolute value bars:

|x|=|y||4i+3|=|24i|
x=+y(4i+3)=(24i)
x=y(4i+3)=(24i)
+x=y(4i+3)=(24i)
x=y(4i+3)=(24i)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4i+3|=|24i|
x=+y , +x=y(4i+3)=(24i)
x=y , x=y(4i+3)=(24i)

3. Solve the two equations for i

7 additional steps

(-4i+3)=-24i

Subtract from both sides:

(-4i+3)-3=(-24i)-3

Simplify the arithmetic:

-4i=(-24i)-3

Add to both sides:

(-4i)+24i=((-24i)-3)+24i

Simplify the arithmetic:

20i=((-24i)-3)+24i

Group like terms:

20i=(-24i+24i)-3

Simplify the arithmetic:

20i=3

Divide both sides by :

(20i)20=-320

Simplify the fraction:

i=-320

12 additional steps

(-4i+3)=--24i

Group like terms:

(-4i+3)=(-1·-24)i

Multiply the coefficients:

(-4i+3)=24i

Subtract from both sides:

(-4i+3)-24i=(24i)-24i

Group like terms:

(-4i-24i)+3=(24i)-24i

Simplify the arithmetic:

-28i+3=(24i)-24i

Simplify the arithmetic:

28i+3=0

Subtract from both sides:

(-28i+3)-3=0-3

Simplify the arithmetic:

28i=03

Simplify the arithmetic:

28i=3

Divide both sides by :

(-28i)-28=-3-28

Cancel out the negatives:

28i28=-3-28

Simplify the fraction:

i=-3-28

Cancel out the negatives:

i=328

4. List the solutions

i=-320,328
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|4i+3|
y=|24i|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.