Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=14
x=\frac{1}{4}
Decimal form: x=0.25
x=0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+3|=2|x+1|
without the absolute value bars:

|x|=|y||2x+3|=2|x+1|
x=+y(2x+3)=2(x+1)
x=y(2x+3)=2((x+1))
+x=y(2x+3)=2(x+1)
x=y(2x+3)=2(x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+3|=2|x+1|
x=+y , +x=y(2x+3)=2(x+1)
x=y , x=y(2x+3)=2((x+1))

2. Solve the two equations for x

13 additional steps

(-2x+3)=2·(x+1)

Expand the parentheses:

(-2x+3)=2x+2·1

Simplify the arithmetic:

(-2x+3)=2x+2

Subtract from both sides:

(-2x+3)-2x=(2x+2)-2x

Group like terms:

(-2x-2x)+3=(2x+2)-2x

Simplify the arithmetic:

-4x+3=(2x+2)-2x

Group like terms:

-4x+3=(2x-2x)+2

Simplify the arithmetic:

4x+3=2

Subtract from both sides:

(-4x+3)-3=2-3

Simplify the arithmetic:

4x=23

Simplify the arithmetic:

4x=1

Divide both sides by :

(-4x)-4=-1-4

Cancel out the negatives:

4x4=-1-4

Simplify the fraction:

x=-1-4

Cancel out the negatives:

x=14

10 additional steps

(-2x+3)=2·(-(x+1))

Expand the parentheses:

(-2x+3)=2·(-x-1)

(-2x+3)=2·-x+2·-1

Group like terms:

(-2x+3)=(2·-1)x+2·-1

Multiply the coefficients:

(-2x+3)=-2x+2·-1

Simplify the arithmetic:

(-2x+3)=-2x-2

Add to both sides:

(-2x+3)+2x=(-2x-2)+2x

Group like terms:

(-2x+2x)+3=(-2x-2)+2x

Simplify the arithmetic:

3=(-2x-2)+2x

Group like terms:

3=(-2x+2x)-2

Simplify the arithmetic:

3=2

The statement is false:

3=2

The equation is false so it has no solution.

3. List the solutions

x=14
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+3|
y=2|x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.