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Solution - Absolute value equations

Exact form: x=-23,8
x=-\frac{2}{3} , 8
Decimal form: x=0.667,8
x=-0.667 , 8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+3|=|x+5|
without the absolute value bars:

|x|=|y||2x+3|=|x+5|
x=+y(2x+3)=(x+5)
x=y(2x+3)=(x+5)
+x=y(2x+3)=(x+5)
x=y(2x+3)=(x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+3|=|x+5|
x=+y , +x=y(2x+3)=(x+5)
x=y , x=y(2x+3)=(x+5)

2. Solve the two equations for x

11 additional steps

(-2x+3)=(x+5)

Subtract from both sides:

(-2x+3)-x=(x+5)-x

Group like terms:

(-2x-x)+3=(x+5)-x

Simplify the arithmetic:

-3x+3=(x+5)-x

Group like terms:

-3x+3=(x-x)+5

Simplify the arithmetic:

3x+3=5

Subtract from both sides:

(-3x+3)-3=5-3

Simplify the arithmetic:

3x=53

Simplify the arithmetic:

3x=2

Divide both sides by :

(-3x)-3=2-3

Cancel out the negatives:

3x3=2-3

Simplify the fraction:

x=2-3

Move the negative sign from the denominator to the numerator:

x=-23

11 additional steps

(-2x+3)=-(x+5)

Expand the parentheses:

(-2x+3)=-x-5

Add to both sides:

(-2x+3)+x=(-x-5)+x

Group like terms:

(-2x+x)+3=(-x-5)+x

Simplify the arithmetic:

-x+3=(-x-5)+x

Group like terms:

-x+3=(-x+x)-5

Simplify the arithmetic:

x+3=5

Subtract from both sides:

(-x+3)-3=-5-3

Simplify the arithmetic:

x=53

Simplify the arithmetic:

x=8

Multiply both sides by :

-x·-1=-8·-1

Remove the one(s):

x=-8·-1

Simplify the arithmetic:

x=8

3. List the solutions

x=-23,8
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+3|
y=|x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.