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Solution - Absolute value equations

Exact form: a=34
a=\frac{3}{4}
Decimal form: a=0.75
a=0.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2a+3|=2|a|
without the absolute value bars:

|x|=|y||2a+3|=2|a|
x=+y(2a+3)=2(a)
x=y(2a+3)=2((a))
+x=y(2a+3)=2(a)
x=y(2a+3)=2(a)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2a+3|=2|a|
x=+y , +x=y(2a+3)=2(a)
x=y , x=y(2a+3)=2((a))

2. Solve the two equations for a

10 additional steps

(-2a+3)=2a

Subtract from both sides:

(-2a+3)-2a=(2a)-2a

Group like terms:

(-2a-2a)+3=(2a)-2a

Simplify the arithmetic:

-4a+3=(2a)-2a

Simplify the arithmetic:

4a+3=0

Subtract from both sides:

(-4a+3)-3=0-3

Simplify the arithmetic:

4a=03

Simplify the arithmetic:

4a=3

Divide both sides by :

(-4a)-4=-3-4

Cancel out the negatives:

4a4=-3-4

Simplify the fraction:

a=-3-4

Cancel out the negatives:

a=34

6 additional steps

(-2a+3)=2·-a

Group like terms:

(-2a+3)=(2·-1)a

Multiply the coefficients:

(-2a+3)=-2a

Add to both sides:

(-2a+3)+2a=(-2a)+2a

Group like terms:

(-2a+2a)+3=(-2a)+2a

Simplify the arithmetic:

3=(-2a)+2a

Simplify the arithmetic:

3=0

The statement is false:

3=0

The equation is false so it has no solution.

3. List the solutions

a=34
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2a+3|
y=2|a|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.