Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: n=4,-75
n=4 , -\frac{7}{5}
Mixed number form: n=4,-125
n=4 , -1\frac{2}{5}
Decimal form: n=4,1.4
n=4 , -1.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6n+3|=|4n+11|
without the absolute value bars:

|x|=|y||6n+3|=|4n+11|
x=+y(6n+3)=(4n+11)
x=y(6n+3)=(4n+11)
+x=y(6n+3)=(4n+11)
x=y(6n+3)=(4n+11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6n+3|=|4n+11|
x=+y , +x=y(6n+3)=(4n+11)
x=y , x=y(6n+3)=(4n+11)

2. Solve the two equations for n

11 additional steps

(6n+3)=(4n+11)

Subtract from both sides:

(6n+3)-4n=(4n+11)-4n

Group like terms:

(6n-4n)+3=(4n+11)-4n

Simplify the arithmetic:

2n+3=(4n+11)-4n

Group like terms:

2n+3=(4n-4n)+11

Simplify the arithmetic:

2n+3=11

Subtract from both sides:

(2n+3)-3=11-3

Simplify the arithmetic:

2n=113

Simplify the arithmetic:

2n=8

Divide both sides by :

(2n)2=82

Simplify the fraction:

n=82

Find the greatest common factor of the numerator and denominator:

n=(4·2)(1·2)

Factor out and cancel the greatest common factor:

n=4

12 additional steps

(6n+3)=-(4n+11)

Expand the parentheses:

(6n+3)=-4n-11

Add to both sides:

(6n+3)+4n=(-4n-11)+4n

Group like terms:

(6n+4n)+3=(-4n-11)+4n

Simplify the arithmetic:

10n+3=(-4n-11)+4n

Group like terms:

10n+3=(-4n+4n)-11

Simplify the arithmetic:

10n+3=11

Subtract from both sides:

(10n+3)-3=-11-3

Simplify the arithmetic:

10n=113

Simplify the arithmetic:

10n=14

Divide both sides by :

(10n)10=-1410

Simplify the fraction:

n=-1410

Find the greatest common factor of the numerator and denominator:

n=(-7·2)(5·2)

Factor out and cancel the greatest common factor:

n=-75

3. List the solutions

n=4,-75
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6n+3|
y=|4n+11|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.