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Solution - Absolute value equations

Exact form: y=92,-9
y=\frac{9}{2} , -9
Mixed number form: y=412,-9
y=4\frac{1}{2} , -9
Decimal form: y=4.5,9
y=4.5 , -9

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2y9|=|2y+9|
without the absolute value bars:

|x|=|y||2y9|=|2y+9|
x=+y(2y9)=(2y+9)
x=y(2y9)=(2y+9)
+x=y(2y9)=(2y+9)
x=y(2y9)=(2y+9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2y9|=|2y+9|
x=+y , +x=y(2y9)=(2y+9)
x=y , x=y(2y9)=(2y+9)

2. Solve the two equations for y

11 additional steps

(2y-9)=(-2y+9)

Add to both sides:

(2y-9)+2y=(-2y+9)+2y

Group like terms:

(2y+2y)-9=(-2y+9)+2y

Simplify the arithmetic:

4y-9=(-2y+9)+2y

Group like terms:

4y-9=(-2y+2y)+9

Simplify the arithmetic:

4y9=9

Add to both sides:

(4y-9)+9=9+9

Simplify the arithmetic:

4y=9+9

Simplify the arithmetic:

4y=18

Divide both sides by :

(4y)4=184

Simplify the fraction:

y=184

Find the greatest common factor of the numerator and denominator:

y=(9·2)(2·2)

Factor out and cancel the greatest common factor:

y=92

5 additional steps

(2y-9)=-(-2y+9)

Expand the parentheses:

(2y-9)=2y-9

Subtract from both sides:

(2y-9)-2y=(2y-9)-2y

Group like terms:

(2y-2y)-9=(2y-9)-2y

Simplify the arithmetic:

-9=(2y-9)-2y

Group like terms:

-9=(2y-2y)-9

Simplify the arithmetic:

9=9

3. List the solutions

y=92,-9
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2y9|
y=|2y+9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.