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Solution - Absolute value equations

Exact form:

y = 3, \frac{1}{3}

y=3 , \frac{1}{3}

Decimal form:

y = 3, 0.333

y=3 , 0.333

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 y - 2 | = | y + 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 y - 2 \| = \| y + 1 \|$
$x = + y$	$(2 y - 2) = (y + 1)$
$x = - y$	$(2 y - 2) = - (y + 1)$
$+ x = y$	$(2 y - 2) = (y + 1)$
$- x = y$	$- (2 y - 2) = (y + 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 y - 2 \| = \| y + 1 \|$
$x = + y$ , $+ x = y$	$(2 y - 2) = (y + 1)$
$x = - y$ , $- x = y$	$(2 y - 2) = - (y + 1)$

2. Solve the two equations for y

7 additional steps

$(2 y - 2) = (y + 1)$

Subtract from both sides:

$(2 y - 2) - y = (y + 1) - y$

Group like terms:

$(2 y - y) - 2 = (y + 1) - y$

Simplify the arithmetic:

$y - 2 = (y + 1) - y$

Group like terms:

$y - 2 = (y - y) + 1$

Simplify the arithmetic:

$y - 2 = 1$

Add to both sides:

$(y - 2) + 2 = 1 + 2$

Simplify the arithmetic:

$y = 1 + 2$

Simplify the arithmetic:

$y = 3$

10 additional steps

$(2 y - 2) = - (y + 1)$

Expand the parentheses:

$(2 y - 2) = - y - 1$

Add to both sides:

$(2 y - 2) + y = (- y - 1) + y$

Group like terms:

$(2 y + y) - 2 = (- y - 1) + y$

Simplify the arithmetic:

$3 y - 2 = (- y - 1) + y$

Group like terms:

$3 y - 2 = (- y + y) - 1$

Simplify the arithmetic:

$3 y - 2 = - 1$

Add to both sides:

$(3 y - 2) + 2 = - 1 + 2$

Simplify the arithmetic:

$3 y = - 1 + 2$

Simplify the arithmetic:

$3 y = 1$

Divide both sides by :

$\frac{(3 y)}{3} = \frac{1}{3}$

Simplify the fraction:

$y = \frac{1}{3}$

3. List the solutions

$y = 3, \frac{1}{3}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 2 y - 2 |$
$y = | y + 1 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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