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Solution - Absolute value equations

Exact form: x=-5,-157
x=-5 , -\frac{15}{7}
Mixed number form: x=-5,-217
x=-5 , -2\frac{1}{7}
Decimal form: x=5,2.143
x=-5 , -2.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x|+|5x15|=0

Add |5x15| to both sides of the equation:

|2x|+|5x15||5x15|=|5x15|

Simplify the arithmetic

|2x|=|5x15|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x|=|5x15|
without the absolute value bars:

|x|=|y||2x|=|5x15|
x=+y(2x)=(5x15)
x=y(2x)=(5x15)
+x=y(2x)=(5x15)
x=y(2x)=(5x15)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x|=|5x15|
x=+y , +x=y(2x)=(5x15)
x=y , x=y(2x)=(5x15)

3. Solve the two equations for x

10 additional steps

2x=-(-5x-15)

Expand the parentheses:

2x=5x+15

Subtract from both sides:

(2x)-5x=(5x+15)-5x

Simplify the arithmetic:

-3x=(5x+15)-5x

Group like terms:

-3x=(5x-5x)+15

Simplify the arithmetic:

3x=15

Divide both sides by :

(-3x)-3=15-3

Cancel out the negatives:

3x3=15-3

Simplify the fraction:

x=15-3

Move the negative sign from the denominator to the numerator:

x=-153

Find the greatest common factor of the numerator and denominator:

x=(-5·3)(1·3)

Factor out and cancel the greatest common factor:

x=5

6 additional steps

2x=-(-(-5x-15))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

2x=5x15

Add to both sides:

(2x)+5x=(-5x-15)+5x

Simplify the arithmetic:

7x=(-5x-15)+5x

Group like terms:

7x=(-5x+5x)-15

Simplify the arithmetic:

7x=15

Divide both sides by :

(7x)7=-157

Simplify the fraction:

x=-157

4. List the solutions

x=-5,-157
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x|
y=|5x15|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.