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Solution - Absolute value equations

Exact form: x=14,316
x=\frac{1}{4} , \frac{3}{16}
Decimal form: x=0.25,0.188
x=0.25 , 0.188

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x|=|14x3|
without the absolute value bars:

|x|=|y||2x|=|14x3|
x=+y(2x)=(14x3)
x=y(2x)=(14x3)
+x=y(2x)=(14x3)
x=y(2x)=(14x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x|=|14x3|
x=+y , +x=y(2x)=(14x3)
x=y , x=y(2x)=(14x3)

2. Solve the two equations for x

9 additional steps

2x=(14x-3)

Subtract from both sides:

(2x)-14x=(14x-3)-14x

Simplify the arithmetic:

-12x=(14x-3)-14x

Group like terms:

-12x=(14x-14x)-3

Simplify the arithmetic:

12x=3

Divide both sides by :

(-12x)-12=-3-12

Cancel out the negatives:

12x12=-3-12

Simplify the fraction:

x=-3-12

Cancel out the negatives:

x=312

Find the greatest common factor of the numerator and denominator:

x=(1·3)(4·3)

Factor out and cancel the greatest common factor:

x=14

6 additional steps

2x=-(14x-3)

Expand the parentheses:

2x=14x+3

Add to both sides:

(2x)+14x=(-14x+3)+14x

Simplify the arithmetic:

16x=(-14x+3)+14x

Group like terms:

16x=(-14x+14x)+3

Simplify the arithmetic:

16x=3

Divide both sides by :

(16x)16=316

Simplify the fraction:

x=316

3. List the solutions

x=14,316
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x|
y=|14x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.