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Solution - Absolute value equations

Exact form: =83,43
=\frac{8}{3} , \frac{4}{3}
Mixed number form: =223,113
=2\frac{2}{3} , 1\frac{1}{3}
Decimal form: =2.667,1.333
=2.667 , 1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|+2|=3|x2|
without the absolute value bars:

|x|=|y||+2|=3|x2|
x=+y(+2)=3(x2)
x=y(+2)=3((x2))
+x=y(+2)=3(x2)
x=y(+2)=3(x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||+2|=3|x2|
x=+y , +x=y(+2)=3(x2)
x=y , x=y(+2)=3((x2))

2. Solve the two equations for

7 additional steps

(2)=3·(x-2)

Expand the parentheses:

(2)=3x+3·-2

Simplify the arithmetic:

(2)=3x-6

Swap sides:

3x-6=(2)

Add to both sides:

(3x-6)+6=(2)+6

Simplify the arithmetic:

3x=(2)+6

Simplify the arithmetic:

3x=8

Divide both sides by :

(3x)3=83

Simplify the fraction:

x=83

12 additional steps

(2)=3·(-(x-2))

Expand the parentheses:

(2)=3·(-x+2)

(2)=3·-x+3·2

Group like terms:

(2)=(3·-1)x+3·2

Multiply the coefficients:

(2)=-3x+3·2

Simplify the arithmetic:

(2)=-3x+6

Swap sides:

-3x+6=(2)

Subtract from both sides:

(-3x+6)-6=(2)-6

Simplify the arithmetic:

-3x=(2)-6

Simplify the arithmetic:

3x=4

Divide both sides by :

(-3x)-3=-4-3

Cancel out the negatives:

3x3=-4-3

Simplify the fraction:

x=-4-3

Cancel out the negatives:

x=43

3. List the solutions

=83,43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|+2|
y=3|x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.