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Solution - Absolute value equations

Exact form: x=-37,-7
x=-\frac{3}{7} , -7
Decimal form: x=0.429,7
x=-0.429 , -7

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x9|=|5x+12|
without the absolute value bars:

|x|=|y||2x9|=|5x+12|
x=+y(2x9)=(5x+12)
x=y(2x9)=((5x+12))
+x=y(2x9)=(5x+12)
x=y(2x9)=(5x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x9|=|5x+12|
x=+y , +x=y(2x9)=(5x+12)
x=y , x=y(2x9)=((5x+12))

2. Solve the two equations for x

10 additional steps

(2x-9)=-(5x+12)

Expand the parentheses:

(2x-9)=-5x-12

Add to both sides:

(2x-9)+5x=(-5x-12)+5x

Group like terms:

(2x+5x)-9=(-5x-12)+5x

Simplify the arithmetic:

7x-9=(-5x-12)+5x

Group like terms:

7x-9=(-5x+5x)-12

Simplify the arithmetic:

7x9=12

Add to both sides:

(7x-9)+9=-12+9

Simplify the arithmetic:

7x=12+9

Simplify the arithmetic:

7x=3

Divide both sides by :

(7x)7=-37

Simplify the fraction:

x=-37

14 additional steps

(2x-9)=-(-(5x+12))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(2x-9)=5x+12

Subtract from both sides:

(2x-9)-5x=(5x+12)-5x

Group like terms:

(2x-5x)-9=(5x+12)-5x

Simplify the arithmetic:

-3x-9=(5x+12)-5x

Group like terms:

-3x-9=(5x-5x)+12

Simplify the arithmetic:

3x9=12

Add to both sides:

(-3x-9)+9=12+9

Simplify the arithmetic:

3x=12+9

Simplify the arithmetic:

3x=21

Divide both sides by :

(-3x)-3=21-3

Cancel out the negatives:

3x3=21-3

Simplify the fraction:

x=21-3

Move the negative sign from the denominator to the numerator:

x=-213

Find the greatest common factor of the numerator and denominator:

x=(-7·3)(1·3)

Factor out and cancel the greatest common factor:

x=7

3. List the solutions

x=-37,-7
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x9|
y=|5x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.