Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=11,53
x=11 , \frac{5}{3}
Mixed number form: x=11,123
x=11 , 1\frac{2}{3}
Decimal form: x=11,1.667
x=11 , 1.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x8|=|x+3|
without the absolute value bars:

|x|=|y||2x8|=|x+3|
x=+y(2x8)=(x+3)
x=y(2x8)=(x+3)
+x=y(2x8)=(x+3)
x=y(2x8)=(x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x8|=|x+3|
x=+y , +x=y(2x8)=(x+3)
x=y , x=y(2x8)=(x+3)

2. Solve the two equations for x

7 additional steps

(2x-8)=(x+3)

Subtract from both sides:

(2x-8)-x=(x+3)-x

Group like terms:

(2x-x)-8=(x+3)-x

Simplify the arithmetic:

x-8=(x+3)-x

Group like terms:

x-8=(x-x)+3

Simplify the arithmetic:

x8=3

Add to both sides:

(x-8)+8=3+8

Simplify the arithmetic:

x=3+8

Simplify the arithmetic:

x=11

10 additional steps

(2x-8)=-(x+3)

Expand the parentheses:

(2x-8)=-x-3

Add to both sides:

(2x-8)+x=(-x-3)+x

Group like terms:

(2x+x)-8=(-x-3)+x

Simplify the arithmetic:

3x-8=(-x-3)+x

Group like terms:

3x-8=(-x+x)-3

Simplify the arithmetic:

3x8=3

Add to both sides:

(3x-8)+8=-3+8

Simplify the arithmetic:

3x=3+8

Simplify the arithmetic:

3x=5

Divide both sides by :

(3x)3=53

Simplify the fraction:

x=53

3. List the solutions

x=11,53
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x8|
y=|x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.