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Solution - Absolute value equations

Exact form: x=4,4
x=4 , 4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x8|+|3x+12|=0

Add |3x+12| to both sides of the equation:

|2x8|+|3x+12||3x+12|=|3x+12|

Simplify the arithmetic

|2x8|=|3x+12|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x8|=|3x+12|
without the absolute value bars:

|x|=|y||2x8|=|3x+12|
x=+y(2x8)=(3x+12)
x=y(2x8)=(3x+12)
+x=y(2x8)=(3x+12)
x=y(2x8)=(3x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x8|=|3x+12|
x=+y , +x=y(2x8)=(3x+12)
x=y , x=y(2x8)=(3x+12)

3. Solve the two equations for x

11 additional steps

(2x-8)=-(-3x+12)

Expand the parentheses:

(2x-8)=3x-12

Subtract from both sides:

(2x-8)-3x=(3x-12)-3x

Group like terms:

(2x-3x)-8=(3x-12)-3x

Simplify the arithmetic:

-x-8=(3x-12)-3x

Group like terms:

-x-8=(3x-3x)-12

Simplify the arithmetic:

x8=12

Add to both sides:

(-x-8)+8=-12+8

Simplify the arithmetic:

x=12+8

Simplify the arithmetic:

x=4

Multiply both sides by :

-x·-1=-4·-1

Remove the one(s):

x=-4·-1

Simplify the arithmetic:

x=4

12 additional steps

(2x-8)=-(-(-3x+12))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(2x-8)=-3x+12

Add to both sides:

(2x-8)+3x=(-3x+12)+3x

Group like terms:

(2x+3x)-8=(-3x+12)+3x

Simplify the arithmetic:

5x-8=(-3x+12)+3x

Group like terms:

5x-8=(-3x+3x)+12

Simplify the arithmetic:

5x8=12

Add to both sides:

(5x-8)+8=12+8

Simplify the arithmetic:

5x=12+8

Simplify the arithmetic:

5x=20

Divide both sides by :

(5x)5=205

Simplify the fraction:

x=205

Find the greatest common factor of the numerator and denominator:

x=(4·5)(1·5)

Factor out and cancel the greatest common factor:

x=4

4. List the solutions

x=4,4
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x8|
y=|3x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.