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Solution - Absolute value equations

Exact form: x=1,133
x=1 , \frac{13}{3}
Mixed number form: x=1,413
x=1 , 4\frac{1}{3}
Decimal form: x=1,4.333
x=1 , 4.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x7||x6|=0

Add |x6| to both sides of the equation:

|2x7||x6|+|x6|=|x6|

Simplify the arithmetic

|2x7|=|x6|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x7|=|x6|
without the absolute value bars:

|x|=|y||2x7|=|x6|
x=+y(2x7)=(x6)
x=y(2x7)=((x6))
+x=y(2x7)=(x6)
x=y(2x7)=(x6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x7|=|x6|
x=+y , +x=y(2x7)=(x6)
x=y , x=y(2x7)=((x6))

3. Solve the two equations for x

7 additional steps

(2x-7)=(x-6)

Subtract from both sides:

(2x-7)-x=(x-6)-x

Group like terms:

(2x-x)-7=(x-6)-x

Simplify the arithmetic:

x-7=(x-6)-x

Group like terms:

x-7=(x-x)-6

Simplify the arithmetic:

x7=6

Add to both sides:

(x-7)+7=-6+7

Simplify the arithmetic:

x=6+7

Simplify the arithmetic:

x=1

10 additional steps

(2x-7)=-(x-6)

Expand the parentheses:

(2x-7)=-x+6

Add to both sides:

(2x-7)+x=(-x+6)+x

Group like terms:

(2x+x)-7=(-x+6)+x

Simplify the arithmetic:

3x-7=(-x+6)+x

Group like terms:

3x-7=(-x+x)+6

Simplify the arithmetic:

3x7=6

Add to both sides:

(3x-7)+7=6+7

Simplify the arithmetic:

3x=6+7

Simplify the arithmetic:

3x=13

Divide both sides by :

(3x)3=133

Simplify the fraction:

x=133

4. List the solutions

x=1,133
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x7|
y=|x6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.