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Solution - Absolute value equations

Exact form: x=-85,49
x=-\frac{8}{5} , \frac{4}{9}
Mixed number form: x=-135,49
x=-1\frac{3}{5} , \frac{4}{9}
Decimal form: x=1.6,0.444
x=-1.6 , 0.444

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x6|=|7x+2|
without the absolute value bars:

|x|=|y||2x6|=|7x+2|
x=+y(2x6)=(7x+2)
x=y(2x6)=(7x+2)
+x=y(2x6)=(7x+2)
x=y(2x6)=(7x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x6|=|7x+2|
x=+y , +x=y(2x6)=(7x+2)
x=y , x=y(2x6)=(7x+2)

2. Solve the two equations for x

11 additional steps

(2x-6)=(7x+2)

Subtract from both sides:

(2x-6)-7x=(7x+2)-7x

Group like terms:

(2x-7x)-6=(7x+2)-7x

Simplify the arithmetic:

-5x-6=(7x+2)-7x

Group like terms:

-5x-6=(7x-7x)+2

Simplify the arithmetic:

5x6=2

Add to both sides:

(-5x-6)+6=2+6

Simplify the arithmetic:

5x=2+6

Simplify the arithmetic:

5x=8

Divide both sides by :

(-5x)-5=8-5

Cancel out the negatives:

5x5=8-5

Simplify the fraction:

x=8-5

Move the negative sign from the denominator to the numerator:

x=-85

10 additional steps

(2x-6)=-(7x+2)

Expand the parentheses:

(2x-6)=-7x-2

Add to both sides:

(2x-6)+7x=(-7x-2)+7x

Group like terms:

(2x+7x)-6=(-7x-2)+7x

Simplify the arithmetic:

9x-6=(-7x-2)+7x

Group like terms:

9x-6=(-7x+7x)-2

Simplify the arithmetic:

9x6=2

Add to both sides:

(9x-6)+6=-2+6

Simplify the arithmetic:

9x=2+6

Simplify the arithmetic:

9x=4

Divide both sides by :

(9x)9=49

Simplify the fraction:

x=49

3. List the solutions

x=-85,49
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x6|
y=|7x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.