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Solution - Absolute value equations

Exact form: x=73,5
x=\frac{7}{3} , 5
Mixed number form: x=213,5
x=2\frac{1}{3} , 5
Decimal form: x=2.333,5
x=2.333 , 5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x6|+|x1|=0

Add |x1| to both sides of the equation:

|2x6|+|x1||x1|=|x1|

Simplify the arithmetic

|2x6|=|x1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x6|=|x1|
without the absolute value bars:

|x|=|y||2x6|=|x1|
x=+y(2x6)=(x1)
x=y(2x6)=(x1)
+x=y(2x6)=(x1)
x=y(2x6)=(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x6|=|x1|
x=+y , +x=y(2x6)=(x1)
x=y , x=y(2x6)=(x1)

3. Solve the two equations for x

10 additional steps

(2x-6)=-(x-1)

Expand the parentheses:

(2x-6)=-x+1

Add to both sides:

(2x-6)+x=(-x+1)+x

Group like terms:

(2x+x)-6=(-x+1)+x

Simplify the arithmetic:

3x-6=(-x+1)+x

Group like terms:

3x-6=(-x+x)+1

Simplify the arithmetic:

3x6=1

Add to both sides:

(3x-6)+6=1+6

Simplify the arithmetic:

3x=1+6

Simplify the arithmetic:

3x=7

Divide both sides by :

(3x)3=73

Simplify the fraction:

x=73

8 additional steps

(2x-6)=-(-(x-1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(2x-6)=x-1

Subtract from both sides:

(2x-6)-x=(x-1)-x

Group like terms:

(2x-x)-6=(x-1)-x

Simplify the arithmetic:

x-6=(x-1)-x

Group like terms:

x-6=(x-x)-1

Simplify the arithmetic:

x6=1

Add to both sides:

(x-6)+6=-1+6

Simplify the arithmetic:

x=1+6

Simplify the arithmetic:

x=5

4. List the solutions

x=73,5
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x6|
y=|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.