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Solution - Absolute value equations

Exact form: x=1,15
x=-1 , -15

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x5|+|3x+10|=0

Add |3x+10| to both sides of the equation:

|2x5|+|3x+10||3x+10|=|3x+10|

Simplify the arithmetic

|2x5|=|3x+10|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x5|=|3x+10|
without the absolute value bars:

|x|=|y||2x5|=|3x+10|
x=+y(2x5)=(3x+10)
x=y(2x5)=(3x+10)
+x=y(2x5)=(3x+10)
x=y(2x5)=(3x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x5|=|3x+10|
x=+y , +x=y(2x5)=(3x+10)
x=y , x=y(2x5)=(3x+10)

3. Solve the two equations for x

11 additional steps

(2x-5)=-(3x+10)

Expand the parentheses:

(2x-5)=-3x-10

Add to both sides:

(2x-5)+3x=(-3x-10)+3x

Group like terms:

(2x+3x)-5=(-3x-10)+3x

Simplify the arithmetic:

5x-5=(-3x-10)+3x

Group like terms:

5x-5=(-3x+3x)-10

Simplify the arithmetic:

5x5=10

Add to both sides:

(5x-5)+5=-10+5

Simplify the arithmetic:

5x=10+5

Simplify the arithmetic:

5x=5

Divide both sides by :

(5x)5=-55

Simplify the fraction:

x=-55

Simplify the fraction:

x=1

11 additional steps

(2x-5)=-(-(3x+10))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(2x-5)=3x+10

Subtract from both sides:

(2x-5)-3x=(3x+10)-3x

Group like terms:

(2x-3x)-5=(3x+10)-3x

Simplify the arithmetic:

-x-5=(3x+10)-3x

Group like terms:

-x-5=(3x-3x)+10

Simplify the arithmetic:

x5=10

Add to both sides:

(-x-5)+5=10+5

Simplify the arithmetic:

x=10+5

Simplify the arithmetic:

x=15

Multiply both sides by :

-x·-1=15·-1

Remove the one(s):

x=15·-1

Simplify the arithmetic:

x=15

4. List the solutions

x=1,15
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x5|
y=|3x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.