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Solution - Absolute value equations

Exact form: x=57,1511
x=\frac{5}{7} , \frac{15}{11}
Mixed number form: x=57,1411
x=\frac{5}{7} , 1\frac{4}{11}
Decimal form: x=0.714,1.364
x=0.714 , 1.364

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x5|=|9x10|
without the absolute value bars:

|x|=|y||2x5|=|9x10|
x=+y(2x5)=(9x10)
x=y(2x5)=(9x10)
+x=y(2x5)=(9x10)
x=y(2x5)=(9x10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x5|=|9x10|
x=+y , +x=y(2x5)=(9x10)
x=y , x=y(2x5)=(9x10)

2. Solve the two equations for x

11 additional steps

(2x-5)=(9x-10)

Subtract from both sides:

(2x-5)-9x=(9x-10)-9x

Group like terms:

(2x-9x)-5=(9x-10)-9x

Simplify the arithmetic:

-7x-5=(9x-10)-9x

Group like terms:

-7x-5=(9x-9x)-10

Simplify the arithmetic:

7x5=10

Add to both sides:

(-7x-5)+5=-10+5

Simplify the arithmetic:

7x=10+5

Simplify the arithmetic:

7x=5

Divide both sides by :

(-7x)-7=-5-7

Cancel out the negatives:

7x7=-5-7

Simplify the fraction:

x=-5-7

Cancel out the negatives:

x=57

10 additional steps

(2x-5)=-(9x-10)

Expand the parentheses:

(2x-5)=-9x+10

Add to both sides:

(2x-5)+9x=(-9x+10)+9x

Group like terms:

(2x+9x)-5=(-9x+10)+9x

Simplify the arithmetic:

11x-5=(-9x+10)+9x

Group like terms:

11x-5=(-9x+9x)+10

Simplify the arithmetic:

11x5=10

Add to both sides:

(11x-5)+5=10+5

Simplify the arithmetic:

11x=10+5

Simplify the arithmetic:

11x=15

Divide both sides by :

(11x)11=1511

Simplify the fraction:

x=1511

3. List the solutions

x=57,1511
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x5|
y=|9x10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.