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Solution - Absolute value equations

Exact form: x=-73,37
x=-\frac{7}{3} , \frac{3}{7}
Mixed number form: x=-213,37
x=-2\frac{1}{3} , \frac{3}{7}
Decimal form: x=2.333,0.429
x=-2.333 , 0.429

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x5|=|5x+2|
without the absolute value bars:

|x|=|y||2x5|=|5x+2|
x=+y(2x5)=(5x+2)
x=y(2x5)=(5x+2)
+x=y(2x5)=(5x+2)
x=y(2x5)=(5x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x5|=|5x+2|
x=+y , +x=y(2x5)=(5x+2)
x=y , x=y(2x5)=(5x+2)

2. Solve the two equations for x

11 additional steps

(2x-5)=(5x+2)

Subtract from both sides:

(2x-5)-5x=(5x+2)-5x

Group like terms:

(2x-5x)-5=(5x+2)-5x

Simplify the arithmetic:

-3x-5=(5x+2)-5x

Group like terms:

-3x-5=(5x-5x)+2

Simplify the arithmetic:

3x5=2

Add to both sides:

(-3x-5)+5=2+5

Simplify the arithmetic:

3x=2+5

Simplify the arithmetic:

3x=7

Divide both sides by :

(-3x)-3=7-3

Cancel out the negatives:

3x3=7-3

Simplify the fraction:

x=7-3

Move the negative sign from the denominator to the numerator:

x=-73

10 additional steps

(2x-5)=-(5x+2)

Expand the parentheses:

(2x-5)=-5x-2

Add to both sides:

(2x-5)+5x=(-5x-2)+5x

Group like terms:

(2x+5x)-5=(-5x-2)+5x

Simplify the arithmetic:

7x-5=(-5x-2)+5x

Group like terms:

7x-5=(-5x+5x)-2

Simplify the arithmetic:

7x5=2

Add to both sides:

(7x-5)+5=-2+5

Simplify the arithmetic:

7x=2+5

Simplify the arithmetic:

7x=3

Divide both sides by :

(7x)7=37

Simplify the fraction:

x=37

3. List the solutions

x=-73,37
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x5|
y=|5x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.