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Solution - Absolute value equations

Exact form: x=-14,-138
x=-\frac{1}{4} , -\frac{13}{8}
Mixed number form: x=-14,-158
x=-\frac{1}{4} , -1\frac{5}{8}
Decimal form: x=0.25,1.625
x=-0.25 , -1.625

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x5|=|10x8|
without the absolute value bars:

|x|=|y||2x5|=|10x8|
x=+y(2x5)=(10x8)
x=y(2x5)=(10x8)
+x=y(2x5)=(10x8)
x=y(2x5)=(10x8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x5|=|10x8|
x=+y , +x=y(2x5)=(10x8)
x=y , x=y(2x5)=(10x8)

2. Solve the two equations for x

11 additional steps

(2x-5)=(-10x-8)

Add to both sides:

(2x-5)+10x=(-10x-8)+10x

Group like terms:

(2x+10x)-5=(-10x-8)+10x

Simplify the arithmetic:

12x-5=(-10x-8)+10x

Group like terms:

12x-5=(-10x+10x)-8

Simplify the arithmetic:

12x5=8

Add to both sides:

(12x-5)+5=-8+5

Simplify the arithmetic:

12x=8+5

Simplify the arithmetic:

12x=3

Divide both sides by :

(12x)12=-312

Simplify the fraction:

x=-312

Find the greatest common factor of the numerator and denominator:

x=(-1·3)(4·3)

Factor out and cancel the greatest common factor:

x=-14

12 additional steps

(2x-5)=-(-10x-8)

Expand the parentheses:

(2x-5)=10x+8

Subtract from both sides:

(2x-5)-10x=(10x+8)-10x

Group like terms:

(2x-10x)-5=(10x+8)-10x

Simplify the arithmetic:

-8x-5=(10x+8)-10x

Group like terms:

-8x-5=(10x-10x)+8

Simplify the arithmetic:

8x5=8

Add to both sides:

(-8x-5)+5=8+5

Simplify the arithmetic:

8x=8+5

Simplify the arithmetic:

8x=13

Divide both sides by :

(-8x)-8=13-8

Cancel out the negatives:

8x8=13-8

Simplify the fraction:

x=13-8

Move the negative sign from the denominator to the numerator:

x=-138

3. List the solutions

x=-14,-138
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x5|
y=|10x8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.