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Solution - Absolute value equations

Exact form: x=-1,75
x=-1 , \frac{7}{5}
Mixed number form: x=-1,125
x=-1 , 1\frac{2}{5}
Decimal form: x=1,1.4
x=-1 , 1.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x4|=3|x1|
without the absolute value bars:

|x|=|y||2x4|=3|x1|
x=+y(2x4)=3(x1)
x=y(2x4)=3((x1))
+x=y(2x4)=3(x1)
x=y(2x4)=3(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x4|=3|x1|
x=+y , +x=y(2x4)=3(x1)
x=y , x=y(2x4)=3((x1))

2. Solve the two equations for x

12 additional steps

(2x-4)=3·(x-1)

Expand the parentheses:

(2x-4)=3x+3·-1

Simplify the arithmetic:

(2x-4)=3x-3

Subtract from both sides:

(2x-4)-3x=(3x-3)-3x

Group like terms:

(2x-3x)-4=(3x-3)-3x

Simplify the arithmetic:

-x-4=(3x-3)-3x

Group like terms:

-x-4=(3x-3x)-3

Simplify the arithmetic:

x4=3

Add to both sides:

(-x-4)+4=-3+4

Simplify the arithmetic:

x=3+4

Simplify the arithmetic:

x=1

Multiply both sides by :

-x·-1=1·-1

Remove the one(s):

x=1·-1

Remove the one(s):

x=1

14 additional steps

(2x-4)=3·(-(x-1))

Expand the parentheses:

(2x-4)=3·(-x+1)

(2x-4)=3·-x+3·1

Group like terms:

(2x-4)=(3·-1)x+3·1

Multiply the coefficients:

(2x-4)=-3x+3·1

Simplify the arithmetic:

(2x-4)=-3x+3

Add to both sides:

(2x-4)+3x=(-3x+3)+3x

Group like terms:

(2x+3x)-4=(-3x+3)+3x

Simplify the arithmetic:

5x-4=(-3x+3)+3x

Group like terms:

5x-4=(-3x+3x)+3

Simplify the arithmetic:

5x4=3

Add to both sides:

(5x-4)+4=3+4

Simplify the arithmetic:

5x=3+4

Simplify the arithmetic:

5x=7

Divide both sides by :

(5x)5=75

Simplify the fraction:

x=75

3. List the solutions

x=-1,75
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x4|
y=3|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.