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Solution - Absolute value equations

Exact form: x=-3,13
x=-3 , \frac{1}{3}
Decimal form: x=3,0.333
x=-3 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x4|=|4x+2|
without the absolute value bars:

|x|=|y||2x4|=|4x+2|
x=+y(2x4)=(4x+2)
x=y(2x4)=(4x+2)
+x=y(2x4)=(4x+2)
x=y(2x4)=(4x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x4|=|4x+2|
x=+y , +x=y(2x4)=(4x+2)
x=y , x=y(2x4)=(4x+2)

2. Solve the two equations for x

13 additional steps

(2x-4)=(4x+2)

Subtract from both sides:

(2x-4)-4x=(4x+2)-4x

Group like terms:

(2x-4x)-4=(4x+2)-4x

Simplify the arithmetic:

-2x-4=(4x+2)-4x

Group like terms:

-2x-4=(4x-4x)+2

Simplify the arithmetic:

2x4=2

Add to both sides:

(-2x-4)+4=2+4

Simplify the arithmetic:

2x=2+4

Simplify the arithmetic:

2x=6

Divide both sides by :

(-2x)-2=6-2

Cancel out the negatives:

2x2=6-2

Simplify the fraction:

x=6-2

Move the negative sign from the denominator to the numerator:

x=-62

Find the greatest common factor of the numerator and denominator:

x=(-3·2)(1·2)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(2x-4)=-(4x+2)

Expand the parentheses:

(2x-4)=-4x-2

Add to both sides:

(2x-4)+4x=(-4x-2)+4x

Group like terms:

(2x+4x)-4=(-4x-2)+4x

Simplify the arithmetic:

6x-4=(-4x-2)+4x

Group like terms:

6x-4=(-4x+4x)-2

Simplify the arithmetic:

6x4=2

Add to both sides:

(6x-4)+4=-2+4

Simplify the arithmetic:

6x=2+4

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=26

Simplify the fraction:

x=26

Find the greatest common factor of the numerator and denominator:

x=(1·2)(3·2)

Factor out and cancel the greatest common factor:

x=13

3. List the solutions

x=-3,13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x4|
y=|4x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.