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Solution - Absolute value equations

Exact form: x=125,6
x=\frac{12}{5} , 6
Mixed number form: x=225,6
x=2\frac{2}{5} , 6
Decimal form: x=2.4,6
x=2.4 , 6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x3|=|3x+9|
without the absolute value bars:

|x|=|y||2x3|=|3x+9|
x=+y(2x3)=(3x+9)
x=y(2x3)=(3x+9)
+x=y(2x3)=(3x+9)
x=y(2x3)=(3x+9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x3|=|3x+9|
x=+y , +x=y(2x3)=(3x+9)
x=y , x=y(2x3)=(3x+9)

2. Solve the two equations for x

9 additional steps

(2x-3)=(-3x+9)

Add to both sides:

(2x-3)+3x=(-3x+9)+3x

Group like terms:

(2x+3x)-3=(-3x+9)+3x

Simplify the arithmetic:

5x-3=(-3x+9)+3x

Group like terms:

5x-3=(-3x+3x)+9

Simplify the arithmetic:

5x3=9

Add to both sides:

(5x-3)+3=9+3

Simplify the arithmetic:

5x=9+3

Simplify the arithmetic:

5x=12

Divide both sides by :

(5x)5=125

Simplify the fraction:

x=125

11 additional steps

(2x-3)=-(-3x+9)

Expand the parentheses:

(2x-3)=3x-9

Subtract from both sides:

(2x-3)-3x=(3x-9)-3x

Group like terms:

(2x-3x)-3=(3x-9)-3x

Simplify the arithmetic:

-x-3=(3x-9)-3x

Group like terms:

-x-3=(3x-3x)-9

Simplify the arithmetic:

x3=9

Add to both sides:

(-x-3)+3=-9+3

Simplify the arithmetic:

x=9+3

Simplify the arithmetic:

x=6

Multiply both sides by :

-x·-1=-6·-1

Remove the one(s):

x=-6·-1

Simplify the arithmetic:

x=6

3. List the solutions

x=125,6
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x3|
y=|3x+9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.