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Solution - Absolute value equations

Exact form: x=-34,38
x=-\frac{3}{4} , \frac{3}{8}
Decimal form: x=0.75,0.375
x=-0.75 , 0.375

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x3|=|6x|
without the absolute value bars:

|x|=|y||2x3|=|6x|
x=+y(2x3)=(6x)
x=y(2x3)=(6x)
+x=y(2x3)=(6x)
x=y(2x3)=(6x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x3|=|6x|
x=+y , +x=y(2x3)=(6x)
x=y , x=y(2x3)=(6x)

2. Solve the two equations for x

10 additional steps

(2x-3)=6x

Subtract from both sides:

(2x-3)-6x=(6x)-6x

Group like terms:

(2x-6x)-3=(6x)-6x

Simplify the arithmetic:

-4x-3=(6x)-6x

Simplify the arithmetic:

4x3=0

Add to both sides:

(-4x-3)+3=0+3

Simplify the arithmetic:

4x=0+3

Simplify the arithmetic:

4x=3

Divide both sides by :

(-4x)-4=3-4

Cancel out the negatives:

4x4=3-4

Simplify the fraction:

x=3-4

Move the negative sign from the denominator to the numerator:

x=-34

7 additional steps

(2x-3)=-6x

Add to both sides:

(2x-3)+3=(-6x)+3

Simplify the arithmetic:

2x=(-6x)+3

Add to both sides:

(2x)+6x=((-6x)+3)+6x

Simplify the arithmetic:

8x=((-6x)+3)+6x

Group like terms:

8x=(-6x+6x)+3

Simplify the arithmetic:

8x=3

Divide both sides by :

(8x)8=38

Simplify the fraction:

x=38

3. List the solutions

x=-34,38
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x3|
y=|6x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.