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Solution - Absolute value equations

Exact form: x=-2,13
x=-2 , \frac{1}{3}
Decimal form: x=2,0.333
x=-2 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x3|=|4x+1|
without the absolute value bars:

|x|=|y||2x3|=|4x+1|
x=+y(2x3)=(4x+1)
x=y(2x3)=(4x+1)
+x=y(2x3)=(4x+1)
x=y(2x3)=(4x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x3|=|4x+1|
x=+y , +x=y(2x3)=(4x+1)
x=y , x=y(2x3)=(4x+1)

2. Solve the two equations for x

13 additional steps

(2x-3)=(4x+1)

Subtract from both sides:

(2x-3)-4x=(4x+1)-4x

Group like terms:

(2x-4x)-3=(4x+1)-4x

Simplify the arithmetic:

-2x-3=(4x+1)-4x

Group like terms:

-2x-3=(4x-4x)+1

Simplify the arithmetic:

2x3=1

Add to both sides:

(-2x-3)+3=1+3

Simplify the arithmetic:

2x=1+3

Simplify the arithmetic:

2x=4

Divide both sides by :

(-2x)-2=4-2

Cancel out the negatives:

2x2=4-2

Simplify the fraction:

x=4-2

Move the negative sign from the denominator to the numerator:

x=-42

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(2x-3)=-(4x+1)

Expand the parentheses:

(2x-3)=-4x-1

Add to both sides:

(2x-3)+4x=(-4x-1)+4x

Group like terms:

(2x+4x)-3=(-4x-1)+4x

Simplify the arithmetic:

6x-3=(-4x-1)+4x

Group like terms:

6x-3=(-4x+4x)-1

Simplify the arithmetic:

6x3=1

Add to both sides:

(6x-3)+3=-1+3

Simplify the arithmetic:

6x=1+3

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=26

Simplify the fraction:

x=26

Find the greatest common factor of the numerator and denominator:

x=(1·2)(3·2)

Factor out and cancel the greatest common factor:

x=13

3. List the solutions

x=-2,13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x3|
y=|4x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.