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Solution - Absolute value equations

Exact form: x=-13,37
x=-\frac{1}{3} , \frac{3}{7}
Decimal form: x=0.333,0.429
x=-0.333 , 0.429

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x2|=|5x1|
without the absolute value bars:

|x|=|y||2x2|=|5x1|
x=+y(2x2)=(5x1)
x=y(2x2)=(5x1)
+x=y(2x2)=(5x1)
x=y(2x2)=(5x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x2|=|5x1|
x=+y , +x=y(2x2)=(5x1)
x=y , x=y(2x2)=(5x1)

2. Solve the two equations for x

11 additional steps

(2x-2)=(5x-1)

Subtract from both sides:

(2x-2)-5x=(5x-1)-5x

Group like terms:

(2x-5x)-2=(5x-1)-5x

Simplify the arithmetic:

-3x-2=(5x-1)-5x

Group like terms:

-3x-2=(5x-5x)-1

Simplify the arithmetic:

3x2=1

Add to both sides:

(-3x-2)+2=-1+2

Simplify the arithmetic:

3x=1+2

Simplify the arithmetic:

3x=1

Divide both sides by :

(-3x)-3=1-3

Cancel out the negatives:

3x3=1-3

Simplify the fraction:

x=1-3

Move the negative sign from the denominator to the numerator:

x=-13

10 additional steps

(2x-2)=-(5x-1)

Expand the parentheses:

(2x-2)=-5x+1

Add to both sides:

(2x-2)+5x=(-5x+1)+5x

Group like terms:

(2x+5x)-2=(-5x+1)+5x

Simplify the arithmetic:

7x-2=(-5x+1)+5x

Group like terms:

7x-2=(-5x+5x)+1

Simplify the arithmetic:

7x2=1

Add to both sides:

(7x-2)+2=1+2

Simplify the arithmetic:

7x=1+2

Simplify the arithmetic:

7x=3

Divide both sides by :

(7x)7=37

Simplify the fraction:

x=37

3. List the solutions

x=-13,37
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x2|
y=|5x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.